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          165. 比较版本号
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        <p><strong>165. 比较版本号</strong></p>
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<h2 id="题目介绍"><a href="#题目介绍" class="headerlink" title="题目介绍"></a>题目介绍</h2><figure class="highlight plaintext"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br><span class="line">25</span><br><span class="line">26</span><br><span class="line">27</span><br><span class="line">28</span><br><span class="line">29</span><br><span class="line">30</span><br></pre></td><td class="code"><pre><span class="line">给你两个版本号 version1 和 version2 ，请你比较它们。</span><br><span class="line">版本号由一个或多个修订号组成，各修订号由一个 &#x27;.&#x27; 连接。每个修订号由 多位数字 组成，可能包含 前导零 。每个版本号至少包含一个字符。修订号从左到右编号，下标从 0 开始，最左边的修订号下标为 0 ，下一个修订号下标为 1 ，以此类推。例如，2.5.33 和 0.1 都是有效的版本号。</span><br><span class="line">比较版本号时，请按从左到右的顺序依次比较它们的修订号。比较修订号时，只需比较 忽略任何前导零后的整数值 。也就是说，修订号 1 和修订号 001 相等 。如果版本号没有指定某个下标处的修订号，则该修订号视为 0 。例如，版本 1.0 小于版本 1.1 ，因为它们下标为 0 的修订号相同，而下标为 1 的修订号分别为 0 和 1 ，0 &lt; 1 。</span><br><span class="line">返回规则如下：</span><br><span class="line">如果 version1 &gt; version2 返回 1，</span><br><span class="line">如果 version1 &lt; version2 返回 -1，</span><br><span class="line">除此之外返回 0。</span><br><span class="line">示例 1：</span><br><span class="line">输入：version1 = &quot;1.01&quot;, version2 = &quot;1.001&quot;</span><br><span class="line">输出：0</span><br><span class="line">解释：忽略前导零，&quot;01&quot; 和 &quot;001&quot; 都表示相同的整数 &quot;1&quot;</span><br><span class="line">示例 2：</span><br><span class="line">输入：version1 = &quot;1.0&quot;, version2 = &quot;1.0.0&quot;</span><br><span class="line">输出：0</span><br><span class="line">解释：version1 没有指定下标为 2 的修订号，即视为 &quot;0&quot;</span><br><span class="line">示例 3：</span><br><span class="line">输入：version1 = &quot;0.1&quot;, version2 = &quot;1.1&quot;</span><br><span class="line">输出：-1</span><br><span class="line">解释：version1 中下标为 0 的修订号是 &quot;0&quot;，version2 中下标为 0 的修订号是 &quot;1&quot; 。0 &lt; 1，所以 version1 &lt; version2</span><br><span class="line">示例 4：</span><br><span class="line">输入：version1 = &quot;1.0.1&quot;, version2 = &quot;1&quot;</span><br><span class="line">输出：1</span><br><span class="line">示例 5：</span><br><span class="line">输入：version1 = &quot;7.5.2.4&quot;, version2 = &quot;7.5.3&quot;</span><br><span class="line">输出：-1</span><br><span class="line">提示：</span><br><span class="line">1 &lt;= version1.length, version2.length &lt;= 500</span><br><span class="line">version1 和 version2 仅包含数字和 &#x27;.&#x27;</span><br><span class="line">version1 和 version2 都是 有效版本号</span><br><span class="line">version1 和 version2 的所有修订号都可以存储在 32 位整数 中</span><br></pre></td></tr></table></figure>

<h2 id="解题思路"><a href="#解题思路" class="headerlink" title="解题思路"></a>解题思路</h2><h3 id="第一种：字符串分割"><a href="#第一种：字符串分割" class="headerlink" title="第一种：字符串分割"></a>第一种：字符串分割</h3><ol>
<li>将版本号按照 <code>.</code> 分割。因为版本号长度不等，所以需要补全，空位补 <code>0</code>，按照最大长度；</li>
<li>遍历从左到右比较相同下标索引的值。</li>
</ol>
<ul>
<li>注意：比较时需要将字符串强制转换为 <code>int</code></li>
</ul>
<h3 id="第二种：双指针"><a href="#第二种：双指针" class="headerlink" title="第二种：双指针"></a>第二种：双指针</h3><p>定义双指针，获取对应的每个修订号，比较每个修订号。</p>
<h2 id="代码"><a href="#代码" class="headerlink" title="代码"></a>代码</h2><h3 id="第一种：字符串分割-1"><a href="#第一种：字符串分割-1" class="headerlink" title="第一种：字符串分割"></a>第一种：字符串分割</h3><figure class="highlight python"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br></pre></td><td class="code"><pre><span class="line"><span class="class"><span class="keyword">class</span> <span class="title">Solution</span>:</span></span><br><span class="line">    <span class="function"><span class="keyword">def</span> <span class="title">compareVersion</span>(<span class="params">self, version1: <span class="built_in">str</span>, version2: <span class="built_in">str</span></span>) -&gt; <span class="built_in">int</span>:</span></span><br><span class="line">        v1_list = version1.split(<span class="string">&quot;.&quot;</span>)</span><br><span class="line">        v2_list = version2.split(<span class="string">&quot;.&quot;</span>)</span><br><span class="line">        len_ = <span class="built_in">min</span>(<span class="built_in">len</span>(v1_list), <span class="built_in">len</span>(v2_list))</span><br><span class="line">        <span class="keyword">for</span> i <span class="keyword">in</span> <span class="built_in">range</span>(len_):</span><br><span class="line">            v1_i_int = <span class="built_in">int</span>(v1_list[i])</span><br><span class="line">            v2_i_int = <span class="built_in">int</span>(v2_list[i])</span><br><span class="line">            <span class="keyword">if</span> v1_i_int &lt; v2_i_int:</span><br><span class="line">                <span class="keyword">return</span> -<span class="number">1</span></span><br><span class="line">            <span class="keyword">elif</span> v1_i_int &gt; v2_i_int:</span><br><span class="line">                <span class="keyword">return</span> <span class="number">1</span></span><br><span class="line">        <span class="keyword">if</span> len_ &lt; <span class="built_in">len</span>(v1_list):</span><br><span class="line">            new_list = [i <span class="keyword">for</span> i <span class="keyword">in</span> v1_list[len_:] <span class="keyword">if</span> <span class="built_in">int</span>(i) != <span class="number">0</span>]</span><br><span class="line">            <span class="keyword">if</span> new_list:</span><br><span class="line">                <span class="keyword">return</span> <span class="number">1</span></span><br><span class="line">        <span class="keyword">elif</span> len_ &lt; <span class="built_in">len</span>(v2_list):</span><br><span class="line">            new_list = [i <span class="keyword">for</span> i <span class="keyword">in</span> v2_list[len_:] <span class="keyword">if</span> <span class="built_in">int</span>(i) != <span class="number">0</span>]</span><br><span class="line">            <span class="keyword">if</span> new_list:</span><br><span class="line">                <span class="keyword">return</span> -<span class="number">1</span></span><br><span class="line">        <span class="keyword">return</span> <span class="number">0</span></span><br></pre></td></tr></table></figure>
<h3 id="第二种：双指针-1"><a href="#第二种：双指针-1" class="headerlink" title="第二种：双指针"></a>第二种：双指针</h3><figure class="highlight python"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br><span class="line">12</span><br><span class="line">13</span><br><span class="line">14</span><br><span class="line">15</span><br><span class="line">16</span><br><span class="line">17</span><br><span class="line">18</span><br><span class="line">19</span><br><span class="line">20</span><br><span class="line">21</span><br><span class="line">22</span><br><span class="line">23</span><br><span class="line">24</span><br><span class="line">25</span><br><span class="line">26</span><br><span class="line">27</span><br><span class="line">28</span><br><span class="line">29</span><br><span class="line">30</span><br><span class="line">31</span><br><span class="line">32</span><br><span class="line">33</span><br><span class="line">34</span><br><span class="line">35</span><br><span class="line">36</span><br><span class="line">37</span><br><span class="line">38</span><br><span class="line">39</span><br><span class="line">40</span><br></pre></td><td class="code"><pre><span class="line"><span class="class"><span class="keyword">class</span> <span class="title">Solution</span>:</span></span><br><span class="line">    <span class="function"><span class="keyword">def</span> <span class="title">compareVersion</span>(<span class="params">self, version1: <span class="built_in">str</span>, version2: <span class="built_in">str</span></span>) -&gt; <span class="built_in">int</span>:</span></span><br><span class="line">        i = j = <span class="number">0</span></span><br><span class="line">        v1_len = <span class="built_in">len</span>(version1)</span><br><span class="line">        v2_len = <span class="built_in">len</span>(version2)</span><br><span class="line">        <span class="keyword">while</span> i &lt; v1_len <span class="keyword">or</span> j &lt; v2_len:</span><br><span class="line">            v1_i = v2_j = <span class="string">&quot;0&quot;</span></span><br><span class="line">            <span class="keyword">while</span> i &lt; v1_len:</span><br><span class="line">                i_str = version1[i]</span><br><span class="line"></span><br><span class="line">                <span class="keyword">if</span> i_str == <span class="string">&quot;.&quot;</span>:</span><br><span class="line">                    <span class="keyword">break</span></span><br><span class="line">                <span class="keyword">else</span>:</span><br><span class="line">                    v1_i += i_str</span><br><span class="line">                    i += <span class="number">1</span></span><br><span class="line"></span><br><span class="line">            <span class="keyword">while</span> j &lt; v2_len:</span><br><span class="line">                j_str = version2[j]</span><br><span class="line">                <span class="keyword">if</span> j_str == <span class="string">&quot;.&quot;</span>:</span><br><span class="line">                    <span class="keyword">break</span></span><br><span class="line">                <span class="keyword">else</span>:</span><br><span class="line">                    v2_j += j_str</span><br><span class="line">                    j += <span class="number">1</span></span><br><span class="line">            <span class="keyword">if</span> <span class="built_in">int</span>(v1_i) &lt; <span class="built_in">int</span>(v2_j):</span><br><span class="line">                <span class="keyword">return</span> -<span class="number">1</span></span><br><span class="line">            <span class="keyword">elif</span> <span class="built_in">int</span>(v1_i) &gt; <span class="built_in">int</span>(v2_j):</span><br><span class="line">                <span class="keyword">return</span> <span class="number">1</span></span><br><span class="line">            <span class="keyword">else</span>:</span><br><span class="line">                i += <span class="number">1</span></span><br><span class="line">                j += <span class="number">1</span></span><br><span class="line"></span><br><span class="line">        <span class="keyword">return</span> <span class="number">0</span></span><br><span class="line"></span><br><span class="line"></span><br><span class="line"><span class="keyword">if</span> __name__ == <span class="string">&#x27;__main__&#x27;</span>:</span><br><span class="line">    v1_str = <span class="string">&quot;1.01&quot;</span></span><br><span class="line">    v2_str = <span class="string">&quot;1.010.0&quot;</span></span><br><span class="line">    s = Solution()</span><br><span class="line">    result = s.compareVersion(v1_str, v2_str)</span><br><span class="line">    <span class="built_in">print</span>(result)</span><br></pre></td></tr></table></figure>


<h2 id="复杂度分析"><a href="#复杂度分析" class="headerlink" title="复杂度分析"></a>复杂度分析</h2><h3 id="第一种：字符串分割-2"><a href="#第一种：字符串分割-2" class="headerlink" title="第一种：字符串分割"></a>第一种：字符串分割</h3><ul>
<li>时间复杂度：<code>O(n + m)</code></li>
<li>空间复杂度：<code>O(n + m)</code><h3 id="第二种：双指针-2"><a href="#第二种：双指针-2" class="headerlink" title="第二种：双指针"></a>第二种：双指针</h3></li>
<li>时间复杂度：<code>O(n + m)</code></li>
<li>空间复杂度：<code>O(1)</code></li>
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